check if the number is in the array or not

Problem

Write a program that asks the user to input 10 integers and stored them in an array and then again asks user to input any single number that store in variable “Num” and program check whether the Num is in the array or not and then print "Number “Num” is in the array" or “Num” is not in the array".

Solution - Code

#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
main()
{
 int arr[10];
 int i,num;
 for (i=0;i<10;i++)
 {
  printf ("Enter number : ");
  scanf ("%d",&arr[i]);
 }
 printf("\nEnter number to check: ");
 scanf ("%d",&num);
 for (i=0;i<10;i++)
 {
  if (num==arr[i])
  {
   printf ("Entered number is in the array\n");
   break;
  }   if (i == 9)
   printf ("Entered number is not in the array\n");
 }
 system("pause");
}

Sample Output

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display the greatest, medium and smallest number using the notation a,b, and c.

Problem

We will read in three integers: a, b and c. We want to construct the logic so that, no matter how these numbers were provided by the user, the output will always be the three numbers printed in order. For example, if we read in 40, 20, 60 into a, b and c respectively, then our logic would printb, a and c in that order. This will give an output of 20, 40 and 60. Or if we read in 70, 10 and 60, then the output would be b, c and a in that order. This will give an output of 10, 60 and 70.

Solution - Code

#include<stdio.h>
main()
{
 int a,b,c;
 printf("Enter 1st Value");
 scanf("%d",&a);
 
 printf("Enter 1st Value");
 scanf("%d",&b);
 
 printf("Enter 1st Value");
 scanf("%d",&c);
 
 
 if(a<b && a<c)
  printf("a");
 else if(b<a && b<c)
  printf("b");
 else
  printf("c");
 
 if(a<b && a>c || a>b && a<c)
  printf("a");
 else if(b<a && b>c ||b>a && b<c)
  printf("b");
 else
  printf("c");
 
 
 if(a>b && a>c)
  printf("a");
 else if(b>a && b>c)
  printf("b");
 else
  printf("c");
 
 system("pause");
}

Sample Output

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display all elements of an array, use pointers to find maximum and minimum element in an array.

Problem

Write three user define functions:

1. void display(int *p, int size);
   The first parameter is the base address of an array and the second parameter is the size of array
   (No of elements in an array). The function displays all the elements in the array. Call this
   function from main function.
2. int max_value (int *p, size);
   this function returns the maximum element of the array pointed by the pointer p. second
   parameter specify the size of array.
3. int min_value (int *p, size);
   this function returns the minimum element of the array pointed by the pointer p. second
   parameter specify the size of array.

Solution - Code

#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
void display(int *,int);
int max_value (int *,int);
int min_value (int *,int);
main()
{
 int max,min,size,i,x,sum=0,avg;
 int num[5];
 size = 5;
 display(num,size);
 max = max_value (num,size);
 printf ("Maximum element : %d\n",max);
 min = min_value (num,size);
 printf ("Minimum element : %d\n",min);
 system("pause");
}
void display(int *p,int size)
{
 int i,num[size],sum=0,avg;
 for (i=0;i<5;i++)
 {
  printf("Enter numbers: ");
  scanf("%d",&num[i]);
 }
 for (i=0;i<5;i++)
 {
  sum = sum + num [i];
 }
 avg =(sum/5);
 printf ("sum = %d\n",sum);
 printf ("average = %d\n",avg);
}
int max_value (int *p,int size)
{
 int num[size];
 int i,max=num[0];
 for (i=0;i<5;i++)
 {
  printf("Enter numbers: ");
  scanf("%d",&num[i]);
 }
 for (i=0;i<5;i++)
 {
  if (max < num[i])
  max=num[i];
 }
 return max;
}
int min_value (int *p,int size)
{
 int num[size];
 int i,min=num[4];
 for (i=0;i<5;i++)
 {
  printf("Enter numbers: ");
  scanf("%d",&num[i]);
 }
 for (i=5;i>=0;i--)
 {
  if (min > num[i])
  min=num[i];
 }
 return min;
}

Sample Output

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find sum and average of subjects

Problem

Write a program that asks the user to input marks in five different subjects. Then find the sum and average of those marks and print them.
Note: Solve the above problem by using array

Solution - Code

#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
main()
{
 int i,x,sum=0,avg;
 int num[5];
 for (i=0;i<5;i++)
 {
  printf("Enter numbers: ");
  scanf("%d",&num[i]);
 }
 for (i=0;i<5;i++)
 {
  sum = sum + num [i];
 }
 avg =(sum/5);
 printf ("sum = %d\n",sum);
 printf ("average = %d\n",avg);
 system("pause");
}

Sample Output

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how much money will you receive on day 15 if you are given 0.20 paisa's on 1st day and double on each day

Problem

Suppose you are given ten paisa on day 1 and on day 2 you are given twice as much. If each day you are given twice as much money as on the previous day, then on day 15, how much money you will receive? Build a C program to find the solution.
Total money for day 1 is Rs. 0.20
Total money for day 2 is Rs. 0.40
Total money for day 3 is Rs. 0.80
Total money for day 4 is Rs. 1.60
………….

Solution - Code

#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
main()
{
 int i;
 float x=0.20;
 printf("Total money for day 1 = Rs.0.20\n");
 for(i=1;i<=15;i++)
 {
  x = (x*2);
  printf("Total money for day %d = %f\n",i,x);
 }
 system("pause");
}

Sample Output

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