Given the length and breadth of a rectangle, write a program to find whether the area of the rectangle is greater than its perimeter

Hint: The area of the rectangle with length = 5 and breadth = 4 is greater than its perimeter.
          Perimeter of rectangle = 2* (length + breadth)
          Area of rectangle = length * breadth

Code

#include<stdio.h>
#include<conio.h>
int main()
{
int length,breadth,perimeter,area;

printf("enter length and breadth: ");
scanf("%d%d",&length,&breadth);

perimeter=2*(length+breadth);
area=length*breadth;

if(area>perimeter)
printf("\narea is greater than perimeter");
else if(area<perimeter)
printf("area is lesser than perimeter");
else
printf("area and perimeter are equal");

printf ("\n\nPress any key to close.");

getch ();
return 0;
}

Output

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Write a program to output whether the person should be insured or not, his/her premium rate and maximum amount for which he/she can be insured.

Description: An Insurance company follows following rules to calculate premium.

1. If a person’s health is excellent and the person is between 25 and 35 years of age and lives in a city and is a male then the premium is Rs. 4 per thousand and his policy amount cannot exceed Rs. 2 lakhs.
2. If a person satisfies all the above conditions except that the sex is female then the premium is Rs. 3 per thousand and her policy amount cannot exceed Rs. 1 lakh.
3. If a person’s health is poor and the person is between 25 and 35 years of age and lives in a village and is a male then the premium is Rs. 6 per thousand and his policy cannot exceed Rs. 10,000.
4. In all other cases the person is not insured.

Code

#include<stdio.h>
#include<conio.h>
int main()
{
char health,sex,area;
int age;

printf("Enter health condn(e/p),sex(m/f),area(c/v)&age\n");
scanf("%c %c %c %d",&health,&sex,&area,&age);

if(health=='e'&&sex=='m'&&area=='c'&&age>=25&&age<=35)
{
printf("\nInsured\n");
printf("\nPremium rate = Rs. 4 per 1,000\n");
printf("\nmaximum policy amount = Rs. 2,00,000");
}
else
if(health=='e'&&sex=='f'&&area=='c'&&age>=25&&age<=35)
{
printf("\nInsured");
printf("\nPremium Rate = Rs. 3 per 1000");
printf("\nMaximum policy amount = Rs. 1,00,000");
}
else
if(health=='p'&&sex=='m'&&area=='v'&&age>=25&&age<=35)
{
printf("\nInsured");
printf("\nPremium Rate = Rs. 6 per 1,000");
printf("\nMaximum policy amount = Rs. 10,000");
}
else
printf("\nYou cannot be insured\n");

printf ("\n\nPress any key to close.");

getch ();
return 0;
}

Output

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A library charges a fine for every book returned late. For first 5 days the fine is 50 paise, for 6-10 days fine is one rupee and above 10 days fine is 5 rupees. If you return the book after 30 days your membership will be cancelled. Write a program to accept the number of days the member is late to return the book and display the fine or the appropriate message.

Code

#include<stdio.h>
#include<conio.h>
int main()
{
int days;
float fine;

printf("Number of days late: ");
scanf("%d",&days);

if(days<=30)
{
if(days<=5)
fine=0.5;
else if(days>5&&days<=10)
fine=1;
else if(days>10&&days<=30)
fine=5;
printf("you have to pay fine of Rs %f",fine);
}
else
printf("Your membership has been canceled");

printf ("\n\nPress any key to close.");

getch ();
return 0;
}

Output

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Write a program to receive marks in subject A and B and Output whether the student has passed, failed or is allowed to reappear in B.

Description: A university has the following rules for a student to qualify for a degree with A as the
main subject and B as the subsidiary subject:

1. He should get 55 percent or more in A and 45 percent or more in B.
2. If he gets than 55 percent in A he should get 55 percent or more in B. However, he should get at least 45 percent in A.
3. If he gets less than 45 percent in B and 65 percent or more in A he is allowed to reappear in an examination in B to qualify.
4. In all other cases he is declared to have failed.

Code

#include<stdio.h>
#include<conio.h>
int main()
{
int pera,perb;

printf("Enter percentage of A and B: ");
scanf("%d%d",&pera,&perb);

if(pera>=55&&perb>=45)
printf("\n Student is passed");

else if(pera>=45&&pera<55&&perb>=55)
printf("\n Student is passed");

else if(perb<45&&pera>=65)
printf("Student is allowed to reappear in an exam");

else
printf("Student is failed");

printf ("\n\nPress any key to close.");

getch ();
return 0;
}

Output

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Write a program to find the greatest of the three numbers entered through the keyboard using conditional operators.

Code

#include <stdio.h>
#include <conio.h>
int main()
{
int a,b,c;
printf("enter 3 numbers (a,b,c)to find greatest no: ");
scanf("%d%d%d",&a,&b,&c);
(a>b&&a>c)?printf("a is greatest"):((b>a&&b>c)?printf("b is greatest"):printf("c is greatest"));

printf ("\n\nPress any key to close.");

getch ();
return 0;
}

Output

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If the three sides of a triangle are entered through the keyboard, write a program to check whether the triangle is isosceles, equilateral, scalene triangle.

Description: An isosceles triangle is triangle with (at least) two equal sides.
                    An equilateral triangle is a triangle with all three sides of equal length
                    A scalene triangle is a triangle that has three unequal sides

Code

#include <stdio.h>
#include <conio.h>
int main()
{
int side1,side2,side3,h;

printf("Enter 3 sides of triangle: ");
scanf("%d%d%d",&side1,&side2,&side3);

if(side1==side2&&side1==side3)
{
printf("\nEquilateral triangle ");
}

else if(side1==side2||side2==side3||side1==side3)
{
printf("\ntriangle is isoscelses ");
}

else if(side1!=side2&&side2!=side3&&side1!=side3)
printf("\n triangle is scalene");
if(side1>side2&&side1>side3)
{
h=sqrt(side2*side2+side3*side3);

if(side1==h)
printf("\ntriangle is right angled triangle");

else
printf("\ntriangle is not right angled triangle");
}
else if(side2>side1&&side2>side3)
{
h=sqrt(side1*side1+side3*side3);

if(side2==h)
printf("\ntriangle is right angled triangle");

else
printf("\ntriangle is not right angled triangle");
}

else if(side3>side1&&side3>side2)
{
h=sqrt(side1*side1+side2*side2);

if(side3==h)
printf("\ntriangle is right angled triangle");
else
printf("\ntriangle is not right angled triangle");
}
printf ("\n\nPress any key to close.");

getch ();
return 0;
}

Output

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Write a program to check whether a triangle is valid or not, when the three angles of the triangle are entered through the keyboard. A triangle is valid if the sum of all the three angles is equal to 180 degrees.

Code

#include<stdio.h>
#include<conio.h>
int main()
{
int angle1,angle2,angle3,sum;
printf ("Enter three angles of triangle: ");
scanf("%d%d%d",&angle1,&angle2,&angle3);
sum=angle1+angle2+angle3;
if(sum==180)
{
printf("\nTriangle is valid");
}
else
printf("\nTriangle is invalid");

printf ("\n\nPress any key to close.");

getch ();
return 0;
}

Output

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If the ages of three students are input through the keyboard, write a program to determine the youpgest of the three.

Code

#include<stdio.h>
int main()
{
int agea,ageb,agec;
printf ("Enter age of Ali, Shan and irfan: ");
scanf("%d%d%d",&agea,&ageb,&agec);
if(agea<ageb&&agea<agec)
{
printf("\nAli is youngest ");
}
else if(ageb<agea&&ageb<agec)
{
printf("\nShan is youngest");
}
else if(agec<agea&&agec<ageb)
{
printf("\nirfan is youngest");
}

printf ("\n\nPress any key to close.");

getch ();
return 0;
}

Output

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